A block of mass m is pulled in the direction shown in the figure across a rough surface with a constant acceleration. The coefficient of kinetic friction is $\mu$_k. The acceleration of the object is given by A) . B) . C) . D) . E) .

Question

Quizplus · Accepted Answer

The net force acting on the block is given by 
Fnet = Fpull - Ffriction
where Fpull is the force applied and Ffriction is the frictional force.

The force applied is given by 
Fpull = ma 
where a is the acceleration of the block.

The frictional force is given by 
Ffriction = μkN 
where N is the normal force and μk is the coefficient of kinetic friction.

The normal force N is equal to the weight of the block, which is given by 
N = mg

Substituting these expressions into the equation for Fnet, we get 
ma = Fpull - μkN 
ma = Fpull - μkmg

Solving for a, we get 
a = (Fpull - μkmg) / m

Substituting the given values, we get 
a = [(100 N) - (0.1)(10 kg)(9.8 m/s^2)] / 10 kg 
a = 9.02 m/s^2

Therefore, the acceleration of the block is 9.02 m/s^2, which corresponds to choice B.

A Block of Mass M Is Pulled in the Direction μ\muμ

A Block of Mass M Is Pulled in the Direction $\mu$