Let f(x, y) = 2x + 3y - 4. Compute the following. f(1, 0), f(0, 1), f(1, 2)
A) f(1, 0) = - 2, f(0, 1) = - 1, f(1, 2) = 4
B) f(1, 0) = 2, f(0, 1) = 1, f(1, 2) = - 4
C) f(1, 0) = - 3, f(0, 1) = - 2, f(1, 2) = 5
D) f(1, 0) = 3, f(0, 1) = 2, f(1, 2) = - 5

Question

Quizplus · Accepted Answer

To compute f(1, 0), substitute x = 1 and y = 0 into the equation for f:
f(1, 0) = 2(1) + 3(0) - 4 = -2

To compute f(0, 1), substitute x = 0 and y = 1 into the equation for f:
f(0, 1) = 2(0) + 3(1) - 4 = -1

To compute f(1, 2), substitute x = 1 and y = 2 into the equation for f:
f(1, 2) = 2(1) + 3(2) - 4 = 4

Therefore, the best choice is A, with f(1,0) = -2, f(0,1) = -1, and f(1,2) = 4.

Let F(x, Y) = 2x + 3y - 4