Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean $\mu$ = 22.4 kilograms and standard deviation $\sigma$= 4.9 kilograms. Let x be the weight of a fawn in kilograms. Convert the following x interval to a z interval. Round to the nearest hundredth. $$x -2.80 B)z

Question

Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean $\mu$ = 22.4 kilograms and standard deviation $\sigma$= 4.9 kilograms. Let x be the weight of a fawn in kilograms. Convert the following x interval to a z interval. Round to the nearest hundredth. $$x < 36.1$$ A)z > -2.80 B)z < 2.80 C)z < 11.94 D)z < -2.80 E)z > 2.80

Quizplus · Accepted Answer

To convert the given x interval to a z interval, we use the formula $z = \frac{x - \mu}{\sigma}$, where $\mu = 22.4$ kg is the mean, $\sigma = 4.9$ kg is the standard deviation, and $x = 36.1$ kg. Plugging in the values, we get $z = \frac{36.1 - 22.4}{4.9} \approx 2.80$. Therefore, the correct conversion is $z < 2.80$.

Suppose a Certain Species of Fawns Between 1 and 5 μ\muμ

Suppose a Certain Species of Fawns Between 1 and 5 $\mu$