Find the solution to the system of equations. $$\begin{aligned}
3 y - 2 x & = - 2 \
12 y - 8 x & = 1
\end{aligned}$$
A) $\left( \frac { 1 } { 2 } , \frac { 1 } { 4 } \right)$
B) $\left( \frac { 1 } { 4 } , \frac { 1 } { 4 } \right)$
C) $( 3 , - 3 )$
D) $\left( 1 , \frac { 1 } { 4 } \right)$
E) No solution

Question

Find the solution to the system of equations.   $$\begin{aligned}
3 y - 2 x & = - 2 \
12 y - 8 x & = 1
\end{aligned}$$ 
A) $\left( \frac { 1 } { 2 } , \frac { 1 } { 4 } \right)$
B) $\left( \frac { 1 } { 4 } , \frac { 1 } { 4 } \right)$
C) $( 3 , - 3 )$
D) $\left( 1 , \frac { 1 } { 4 } \right)$
E) No solution

Quizplus · Accepted Answer

The second equation is a multiple of the first, but the constants do not match, indicating parallel lines with no intersection point.

Find the Solution to the System of Equations 3y−2x=−212y−8x=1\begin{aligned}3 y - 2 x & = - 2 \\12 y - 8 x & = 1\end{aligned}3y−2x12y−8x​=−2=1​

Find the Solution to the System of Equations $\begin{aligned}3 y - 2 x & = - 2 \\12 y - 8 x & = 1\end{aligned}$