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The Chart Shows the Number of Personal Bankruptcy Filings in Three

Question 134

Multiple Choice

The chart shows the number of personal bankruptcy filings in three City regions during various months of 2001 - 2002.  Jan 01  Jul 01  Jan 02  North 140140140 West 290290230 East 230230190\begin{array} { | l | l | l | l | } \hline & \text { Jan 01 } & \text { Jul 01 } & \text { Jan 02 } \\\hline \text { North } & 140 & 140 & 140 \\\hline \text { West } & 290 & 290 & 230 \\\hline \text { East } & 230 & 230 & 190 \\\hline\end{array} Write a matrix product whose computation gives the total number by which bankruptcy filings in January, 2001, exceeded filings in January, 2002.


A) [011][140140140290290230230230190][111]=[110]\left[ \begin{array} { l l l } 0 & 1 & 1\end{array} \right] \cdot \left[ \begin{array} { l l l } 140 & 140 & 140 \\290 & 290 & 230 \\230 & 230 & 190\end{array} \right] \cdot \left[ \begin{array} { c } 1 \\1 \\- 1\end{array} \right] = [ 110 ]
B) [111][140140140290290230230230190][101]=[90]\left[ \begin{array} { l l l } 1 & 1 & 1\end{array} \right] \cdot \left[ \begin{array} { l l l } 140 & 140 & 140 \\290 & 290 & 230 \\230 & 230 & 190\end{array} \right] \cdot \left[ \begin{array} { c } - 1 \\0 \\- 1\end{array} \right] = [ 90 ]
C) [111][140140140290290230230230190][101]=[100]\left[ \begin{array} { l l l } 1 & 1 & 1\end{array} \right] \cdot \left[ \begin{array} { l l l } 140 & 140 & 140 \\290 & 290 & 230 \\230 & 230 & 190\end{array} \right] \cdot \left[ \begin{array} { c } 1 \\0 \\- 1\end{array} \right] = \left[ \begin{array} { c } 100\end{array} \right]
D) [101][140140140290290230230230190][101]=[80]\left[ \begin{array} { l l l } 1 & 0 & - 1\end{array} \right] \cdot \left[ \begin{array} { l l l } 140 & 140 & 140 \\290 & 290 & 230 \\230 & 230 & 190\end{array} \right] \cdot \left[ \begin{array} { l } 1 \\0 \\1\end{array} \right] = [ 80 ]
E) [111][140140140290290230230230190][101]=[130]\left[ \begin{array} { l l l } 1 & - 1 & 1\end{array} \right] \cdot \left[ \begin{array} { l l l } 140 & 140 & 140 \\290 & 290 & 230 \\230 & 230 & 190\end{array} \right] \cdot \left[ \begin{array} { c } 1 \\0 \\- 1\end{array} \right] = [ 130 ]

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