Compute the product of the two matrices (if possible). $\left[ \begin{array} { c c }
4 & - 1
\end{array} \right] \cdot \left[ \begin{array} { c c c c }
- 3 & 1 & 5 & 2 \
7 & 0 & 6 & 4
\end{array} \right]$
A) $\left[ \begin{array} { l l l l }
- 19 & 4 & 14 & 4
\end{array} \right]$
B) $\left[ \begin{array} { l l l l }
7 & 15 & - 4 & 19
\end{array} \right]$
C) $\left[ \begin{array} { l l l l }
4 & 4 & 14 & - 19
\end{array} \right]$
D) $\left[ \begin{array} { l l l l }
- 19 & - 4 & 14 & - 7
\end{array} \right]$
E) Undefined

Question

Compute the product of the two matrices (if possible).   $\left[ \begin{array} { c c } 
4 & - 1
\end{array} \right] \cdot \left[ \begin{array} { c c c c } 
- 3 & 1 & 5 & 2 \
7 & 0 & 6 & 4
\end{array} \right]$  
A) $\left[ \begin{array} { l l l l } 
- 19 & 4 & 14 & 4
\end{array} \right]$
B) $\left[ \begin{array} { l l l l } 
7 & 15 & - 4 & 19
\end{array} \right]$
C) $\left[ \begin{array} { l l l l } 
4 & 4 & 14 & - 19
\end{array} \right]$
D) $\left[ \begin{array} { l l l l } 
- 19 & - 4 & 14 & - 7
\end{array} \right]$
E) Undefined

Quizplus · Accepted Answer

The product of the two matrices is calculated by multiplying each element of the row of the first matrix by the corresponding element of the column of the second matrix and then adding them up. For this case, the calculation is as follows: $4*(-3) + (-1)*7 = -12 - 7 = -19$ for the first element, $4*1 + (-1)*0 = 4$ for the second element, $4*5 + (-1)*6 = 20 - 6 = 14$ for the third element, and $4*2 + (-1)*4 = 8 - 4 = 4$ for the fourth element. Therefore, the product is $\left[ \begin{array} { l l l l } - 19 & 4 & 14 & 4 \end{array} \right]$.

Compute the Product of the Two Matrices (If Possible) A) [−194144]\left[ \begin{array} { l l l l } - 19 & 4 & 14 & 4\end{array} \right][−19​4​14​4​]

Compute the Product of the Two Matrices (If Possible) A) $\left[ \begin{array} { l l l l } - 19 & 4 & 14 & 4\end{array} \right]$