Maximize
$p = 12 x + 10 y$
subject to
$\begin{aligned}
x + y & \leq 40 \
x & \geq 3 \
- x + 2 y & \geq 0 \
x \geq 0 , y & \geq 0
\end{aligned}$
Please enter your answer as three numbers, separated by commas in the order p, x, y. If there is no solution, enter no solution.

Question

Maximize
​ $p = 12 x + 10 y$ ​
subject to
​ $\begin{aligned}
x + y & \leq 40 \
x & \geq 3 \
- x + 2 y & \geq 0 \
x \geq 0 , y & \geq 0
\end{aligned}$ ​
Please enter your answer as three numbers, separated by commas in the order p, x, y. If there is no solution, enter no solution.

Quizplus · Accepted Answer

The Answer of Maximize
​ $p = 12 x + 10 y$ ​
subject to
​ $\begin{aligned}
x + y & \leq 40 \
x & \geq 3 \
- x + 2 y & \geq 0 \
x \geq 0 , y & \geq 0
\end{aligned}$ ​
Please enter your answer as three numbers, separated by commas in the order p, x, y. If there is no solution, enter no solution.

Maximize ​ p=12x+10yp = 12 x + 10 yp=12x+10y ​ Subject to ​

Maximize
$p = 12 x + 10 y$
Subject to