Recently, buckyballs (C₆₀) became the largest objects with a measured de Broglie wavelength. If the mass of a C₆₀ molecule is 1.20 *10^-²⁴ kg, what will be its de Broglie wavelength if it is moving at a speed of 220 m/sec? A) 2.52 pm B) 2.52 fm C) 2.52 m D) 1.20 pm E) 5.22 m

Question

Quizplus · Accepted Answer

The de Broglie wavelength is calculated using the formula λ = h / (mv), where h is Planck's constant (6.626 x 10^-34 m^2 kg/s), m is the mass, and v is the velocity. Substituting the given values, λ = 6.626 x 10^-34 / (1.20 x 10^-24 kg * 220 m/s) = 2.52 x 10^-12 m, which is 2.52 pm (picometers).

Recently, Buckyballs (C60) Became the Largest Objects with a Measured

Recently, Buckyballs (C₆₀) Became the Largest Objects with a Measured