What is the photon energy of the yellow-orange light ($\lambda$= 589 nm) produced by sodium vapor streetlights? A) 3.37 *10^-¹⁹ J B) 6.63 *10^-¹⁸ J C) 2.99*10^-²⁰ J D) 1.45 *10^-¹⁷ J E) 7.45 * 10^-¹⁶ J

Question

Quizplus · Accepted Answer

The energy of a photon can be calculated using the formula $E = \frac{hc}{\lambda}$, where $h$ is Planck's constant ($6.626 \times 10^{-34} \, \text{J s}$), $c$ is the speed of light ($3.00 \times 10^8 \, \text{m/s}$), and $\lambda$ is the wavelength in meters. For $\lambda = 589 \, \text{nm} = 589 \times 10^{-9} \, \text{m}$, the energy $E$ is approximately $3.37 \times 10^{-19} \, \text{J}$.

What Is the Photon Energy of the Yellow-Orange Light λ\lambdaλ = 589 Nm) Produced by Sodium Vapor Streetlights? A) 3

What Is the Photon Energy of the Yellow-Orange Light $\lambda$ = 589 Nm) Produced by Sodium Vapor Streetlights?
A) 3