What is the energy (E, in J) of the photons emitted by an Ar⁺ laser with a wavelength of $\lambda$ = 488 nm? A) 2.46 * 10¹⁸ J B) 9.69 *10^-²³ J C) 1.36 *10^-³⁶ J D) 4.07 *10^-¹⁹ J E) 2.46 * 10^-¹⁸ J

Question

Quizplus · Accepted Answer

The energy of a photon is given by $E = \frac{hc}{\lambda}$, where $h$ is Planck's constant ($6.626 \times 10^{-34} \, \text{J s}$), $c$ is the speed of light ($3.00 \times 10^8 \, \text{m/s}$), and $\lambda$ is the wavelength in meters. Converting 488 nm to meters and substituting the values gives approximately $4.07 \times 10^{-19} \, \text{J}$.

What Is the Energy (E, in J) of the Photons λ\lambdaλ

What Is the Energy (E, in J) of the Photons $\lambda$