If an X-ray with a wavelength of 154 pm is diffracted at an angle 2$\theta$= 14.6°, according to the Bragg equation (n$\lambda$ = 2 d sin$\theta$), what is the distance between layers of the crystal that give rise to this diffraction? Assume n = 1 in this problem.
A) 610.9 pm
B) 305.5 pm
C) 606.0 pm
D) 1212 pm
E) 198.1 pm

Question

Quizplus · Accepted Answer

Using the Bragg equation:

2d sin(θ) = nλ

where

n = 1 (given)

λ = 154 pm

θ = 14.6°

Substituting the values:

2d sin(14.6°) = 1(154 pm)

d = λ/2sin(θ) = (154 pm)/(2sin(14.6°)) ≈ 606.0 pm

Therefore, the distance between layers of the crystal that give rise to this diffraction is approximately 606.0 pm, which corresponds to choice C.

If an X-Ray with a Wavelength of 154 Pm Is θ\thetaθ

If an X-Ray with a Wavelength of 154 Pm Is $\theta$