PART a Some Fettuccines Are Not Taste Sensations, for No $\begin{array} { l } \text {No L are T.}\\ \text {Some F are not T. }\\ \hline\text {Some F are not L. }\\\end{array}$

PART A Some fettuccines are not taste sensations, for no low fat recipes are taste sensations, and some fettuccines are not low fat recipes.
The form of this argument is: a. $\begin{array} { l } \text {No L are T.}\\ \text {Some F are not T. }\\ \hline\text {Some F are not L. }\\\end{array}$ $\quad$ b. $\begin{array} { l } \text {Some F are not T. }\\ \text {No L are T. }\\ \hline\text {Some F are not L. }\\\end{array}$$\quad$ c. $\begin{array} { l } \text { Some F are not T.}\\ \text { Some F are not L.}\\ \hline\text {No L are T. }\\\end{array}$

d. $\begin{array} { l } \text { No L are T.}\\ \text {Some F are not L.}\\ \hline\text {Some F are not T. }\\\end{array}$$\quad$ e. $\begin{array} { l } \text { Some F are not L.}\\ \text { Some F are not T. }\\ \hline\text { No L are T.}\\\end{array}$ PART B
Which of the following substitutions proves the argument invalid?
A) $F = \text { animals } , L = \text { dogs } , T = \text { cats. }$
B) $\mathrm { L } = \text { fish } \mathrm { T } = \text { mammals. } \mathrm { F } = \text { cats }$
C) $\mathrm { T } = \text { fish, } \mathrm { L } = \text { mammals, } \mathrm { F } = \text { cats. }$
D) $F = \operatorname { dog } s , T = \text { mammals, } L = \text { animals. }$
E) $\mathrm { L } = \operatorname { dog } \mathrm { s } , \mathrm { F } = \text { animals, } \mathrm { T } = \mathrm { fish }$