Suppose a box contains 6 defective transistors and 13 good transistors. If 2 transistors are drawn from the box without replacement, what is the probability that one of the transistors drawn is good G and one of them is defective D?
A)Pr(one G ∩ one
D) =
B)Pr(one G ∩ one
D) =
C)Pr(one G ∩ one
D) =
D)Pr(one G ∩ one
D) =
E)Pr(one G ∩ one
D) =

Question

Suppose a box contains 6 defective transistors and 13 good transistors. If 2 transistors are drawn from the box without replacement, what is the probability that one of the transistors drawn is good G and one of them is defective D? ​
A)Pr(one G ∩ one 
D) = 
B)Pr(one G ∩ one 
D) = 
C)Pr(one G ∩ one 
D) = 
D)Pr(one G ∩ one 
D) = 
E)Pr(one G ∩ one 
D) =

Quizplus · Accepted Answer

The Answer of Suppose a box contains 6 defective transistors and 13 good transistors. If 2 transistors are drawn from the box without replacement, what is the probability that one of the transistors drawn is good G and one of them is defective D? ​
A)Pr(one G ∩ one 
D) = 
B)Pr(one G ∩ one 
D) = 
C)Pr(one G ∩ one 
D) = 
D)Pr(one G ∩ one 
D) = 
E)Pr(one G ∩ one 
D) =

Suppose a Box Contains 6 Defective Transistors and 13 Good