Suppose a box contains 2 defective transistors and 12 good transistors. If 2 transistors are drawn from the box without replacement, what is the probability that the first transistor is good G and the second transistor is defective D?
A)Pr(G first ∩ D second) =
B)Pr(G first ∩ D second) =
C)Pr(G first ∩ D second) =
D)Pr(G first ∩ D second) =
E)Pr(G first ∩ D second) =

Question

Suppose a box contains 2 defective transistors and 12 good transistors. If 2 transistors are drawn from the box without replacement, what is the probability that the first transistor is good G and the second transistor is defective D? ​
A)Pr(G first ∩ D second) = 
B)Pr(G first ∩ D second) = 
C)Pr(G first ∩ D second) = 
D)Pr(G first ∩ D second) = 
E)Pr(G first ∩ D second) =

Quizplus · Accepted Answer

The Answer of Suppose a box contains 2 defective transistors and 12 good transistors. If 2 transistors are drawn from the box without replacement, what is the probability that the first transistor is good G and the second transistor is defective D? ​
A)Pr(G first ∩ D second) = 
B)Pr(G first ∩ D second) = 
C)Pr(G first ∩ D second) = 
D)Pr(G first ∩ D second) = 
E)Pr(G first ∩ D second) =

Suppose a Box Contains 2 Defective Transistors and 12 Good