Solve. -A single bacterium divides every 0.5 hour to produce two complete bacteria. If we start with a colony of 6000 bacteria, after t hours there will be A(t) = 6000 · 2²^t = 6000 · 4^t bacteria. Find A'(t) and A'(1). A) A'(t) = 6000(ln 4)4^t; A'(1) = 33,271 bacteria B) A'(t) = 6000(ln 2)2^t; A'(1) = 8317 bacteria C) A'(t) = 6000(ln 4)2^t; A'(1) = 16,635 bacteria D) A'(t) = 6000(ln 2)4^t; A'(1) = 16,635 bacteria

Question

Quizplus · Accepted Answer

A'(t) = 6000(ln 4)4^t; A'(1) = 33,271 bacteriaThe derivative of A(t) is A'(t) = 6000(ln 4)4^t. At t = 1, A'(1) = 6000(ln 4)4¹ = 33,271 bacteria.

Solve. -A Single Bacterium Divides Every 0.5 Hour to Produce Two