Container 1 has 8 items,3 of which are defective.Container 2 has 5 items,2 of which are defective.If one item is drawn from each container,what is the probability that only one of the items is defective?
A)0.2250
B)0.3000
C)0.0250
D)0.4000
E)0.1500

Question

Quizplus · Accepted Answer

The probability of drawing a non-defective item from Container 1 and a defective item from Container 2 is (5/8) * (2/5) = 0.25. The probability of drawing a defective item from Container 1 and a non-defective item from Container 2 is (3/8) * (3/5) = 0.1125. Adding these probabilities gives 0.25 + 0.1125 = 0.3625, which rounds to 0.4000.

Container 1 Has 8 Items,3 of Which Are Defective