Find a 90 percent confidence interval for the difference between the proportions of group l and group 2.Let p₁ represent the population proportion of the people in group 1 who are in favor of new packaging,and let p₂ represent the population proportion of the people in group 2 who are in favor of new packaging. $\hat { p } _ { 1 }$
= .21, $\hat { p } _ { 2 }$
= .13,n₁ = 300,and n₂ = 400.

Question

Find a 90 percent confidence interval for the difference between the proportions of group l and group 2.Let p₁ represent the population proportion of the people in group 1 who are in favor of new packaging,and let p₂ represent the population proportion of the people in group 2 who are in favor of new packaging.

\hat { p } _ { 1 }

= .21,

\hat { p } _ { 2 }

= .13,n₁ = 300,and n₂ = 400.

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The Answer of Find a 90 percent confidence interval for the difference between the proportions of group l and group 2.Let p₁ represent the population proportion of the people in group 1 who are in favor of new packaging,and let p₂ represent the population proportion of the people in group 2 who are in favor of new packaging. $\hat { p } _ { 1 }$ = .21, $\hat { p } _ { 2 }$ = .13,n₁ = 300,and n₂ = 400.

Find a 90 Percent Confidence Interval for the Difference Between p^1\hat { p } _ { 1 }p^​1​

Find a 90 Percent Confidence Interval for the Difference Between $\hat { p } _ { 1 }$