TABLE 11-7
An agronomist wants to compare the crop yield of 3 varieties of chickpea seeds. She plants 15 fields, 5 with each variety. She then measures the crop yield in bushels per acre. Treating this as a completely randomized design, the results are presented in the table that follows.
$$\begin{array} { c r r r }
\text { Trial } & \text { Smith } & \text { Walsh } & \text { Trevor } \
\hline 1 & 11.1 & 19.0 & 14.6 \
2 & 13.5 & 18.0 & 15.7 \
3 & 15.3 & 19.8 & 16.8 \
4 & 14.6 & 19.6 & 16.7 \
5 & 9.8 & 16.6 & 15.2
\end{array}$$
-Referring to Table 11-7, the null hypothesis should be rejected at 0.005 level of significance.

Question

TABLE 11-7 
 An agronomist wants to compare the crop yield of 3 varieties of chickpea seeds. She plants 15 fields, 5 with each variety. She then measures the crop yield in bushels per acre. Treating this as a completely randomized design, the results are presented in the table that follows.
 $$\begin{array} { c r r r } 
\text { Trial } & \text { Smith } & \text { Walsh } & \text { Trevor } \
\hline 1 & 11.1 & 19.0 & 14.6 \
2 & 13.5 & 18.0 & 15.7 \
3 & 15.3 & 19.8 & 16.8 \
4 & 14.6 & 19.6 & 16.7 \
5 & 9.8 & 16.6 & 15.2
\end{array}$$
-Referring to Table 11-7, the null hypothesis should be rejected at 0.005 level of significance.

Quizplus · Accepted Answer

The F-value is 10.38, which is greater than the critical value of 4.74 at the 0.005 level of significance. Therefore, the null hypothesis should be rejected.

TABLE 11-7 an Agronomist Wants to Compare the Crop

TABLE 11-7
an Agronomist Wants to Compare the Crop