Find $\lim _ { x \rightarrow 7 } \frac { \sqrt { x + 3 } } { x - 5 }$ by direct substitution.
A) $\frac { \sqrt { 23 } } { 2 }$
B) $\frac { 1 } { 7 }$
C) $\frac { 1 } { 2 }$
D) $\sqrt { 10 }$
E) $\frac { \sqrt { 10 } } { 2 }$

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The Answer of Find $\lim _ { x \rightarrow 7 } \frac { \sqrt { x + 3 } } { x - 5 }$ by direct substitution.
A) $\frac { \sqrt { 23 } } { 2 }$
B) $\frac { 1 } { 7 }$
C) $\frac { 1 } { 2 }$
D) $\sqrt { 10 }$
E) $\frac { \sqrt { 10 } } { 2 }$

Find lim⁡x→7x+3x−5\lim _ { x \rightarrow 7 } \frac { \sqrt { x + 3 } } { x - 5 }limx→7​x−5x+3​​

Find $\lim _ { x \rightarrow 7 } \frac { \sqrt { x + 3 } } { x - 5 }$