Find $\lim _ { x \rightarrow 9 } \frac { x - 7 } { x ^ { 2 } + 11 x + 18 }$ by direct substitution.
A)198
B) $\frac { 1 } { 99 }$
C) $\infty$
D)limit does not exist
E)0

Name: Find $\lim _ { x \rightarrow 9 } \frac { x - 7 } { x ^ { 2 } + 11 x + 18 }$ by direct substitution. A)198 B) $\frac { 1 } { 99 }$ C) $\infty$ D)limit does not exist E)0
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Question

Quizplus · Accepted Answer

By directly substituting $x = 9$ into the expression, we get $\frac{9 - 7}{9^2 + 11(9) + 18} = \frac{2}{81 + 99 + 18} = \frac{2}{198} = \frac{1}{99}$.

Find lim⁡x→9x−7x2+11x+18\lim _ { x \rightarrow 9 } \frac { x - 7 } { x ^ { 2 } + 11 x + 18 }limx→9​x2+11x+18x−7​

Find $\lim _ { x \rightarrow 9 } \frac { x - 7 } { x ^ { 2 } + 11 x + 18 }$