Find the limit of the sequence (if it exists). $\alpha _ { n } = \frac { 4 n ^ { 2 } + 1 } { 2 n }$
A) $\lim_ { n \rightarrow \infty } \alpha _ { n } = - 4$
B) $\lim _ { n \rightarrow \infty } \alpha _ { n } = \frac { 1 } { 2 }$
C) $\lim _ { n \rightarrow \infty }\alpha _ { n } = 4$
D) $\lim_ { n \rightarrow \infty } \alpha _ { n } = 0$
E) $\lim_ { n \rightarrow \infty } a _ { n } = \infty$

Question

Find the limit of the sequence (if it exists).   $\alpha _ { n } = \frac { 4 n ^ { 2 } + 1 } { 2 n }$  
A) $\lim_ { n \rightarrow \infty } \alpha _ { n } = - 4$
B) $\lim _ { n \rightarrow \infty } \alpha _ { n } = \frac { 1 } { 2 }$
C) $\lim _ { n \rightarrow \infty }\alpha _ { n } = 4$
D) $\lim_ { n \rightarrow \infty } \alpha _ { n } = 0$
E) $\lim_ { n \rightarrow \infty } a _ { n } = \infty$

Quizplus · Accepted Answer

The Answer of Find the limit of the sequence (if it exists).   $\alpha _ { n } = \frac { 4 n ^ { 2 } + 1 } { 2 n }$  
A) $\lim_ { n \rightarrow \infty } \alpha _ { n } = - 4$
B) $\lim _ { n \rightarrow \infty } \alpha _ { n } = \frac { 1 } { 2 }$
C) $\lim _ { n \rightarrow \infty }\alpha _ { n } = 4$
D) $\lim_ { n \rightarrow \infty } \alpha _ { n } = 0$
E) $\lim_ { n \rightarrow \infty } a _ { n } = \infty$

Find the Limit of the Sequence (If It Exists) αn=4n2+12n\alpha _ { n } = \frac { 4 n ^ { 2 } + 1 } { 2 n }αn​=2n4n2+1​

Find the Limit of the Sequence (If It Exists) $\alpha _ { n } = \frac { 4 n ^ { 2 } + 1 } { 2 n }$