Rewrite $\sum _ { i = 1 } ^ { n } \frac { 4 i + 2 } { n ^ { 2 } }$ as a rational function S(n)and find $\lim S ( n )$ .
A) $S ( n ) = \frac { 2 ( n + 1 ) + 2 } { n } , \lim _ { n \rightarrow \infty } S ( n ) = 2$
B) $S ( n ) = \frac { 2 ( n + 1 ) + 2 } { n ^ { 2 } } , \lim _ { n \rightarrow \infty } S ( n ) = 0$
C) $S ( n ) = \frac { 2 ( n + 1 ) + 2 } { n } , \lim _ { n \rightarrow \infty } S ( n ) = 4$
D) $S ( n ) = \frac { 2 ( n + 1 ) 2 } { n } , \lim _ { n \rightarrow \infty } S ( n ) = 0$
E) $S ( n ) = \frac { 2 n ( n + 1 ) + 2 } { n ^ { 2 } } , \lim _ { n \rightarrow \infty } S ( n ) = 2$

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The Answer of Rewrite $\sum _ { i = 1 } ^ { n } \frac { 4 i + 2 } { n ^ { 2 } }$ as a rational function S(n)and find $\lim S ( n )$ .
A) $S ( n ) = \frac { 2 ( n + 1 ) + 2 } { n } , \lim _ { n \rightarrow \infty } S ( n ) = 2$
B) $S ( n ) = \frac { 2 ( n + 1 ) + 2 } { n ^ { 2 } } , \lim _ { n \rightarrow \infty } S ( n ) = 0$
C) $S ( n ) = \frac { 2 ( n + 1 ) + 2 } { n } , \lim _ { n \rightarrow \infty } S ( n ) = 4$
D) $S ( n ) = \frac { 2 ( n + 1 ) 2 } { n } , \lim _ { n \rightarrow \infty } S ( n ) = 0$
E) $S ( n ) = \frac { 2 n ( n + 1 ) + 2 } { n ^ { 2 } } , \lim _ { n \rightarrow \infty } S ( n ) = 2$

Rewrite ∑i=1n4i+2n2\sum _ { i = 1 } ^ { n } \frac { 4 i + 2 } { n ^ { 2 } }∑i=1n​n24i+2​

Rewrite $\sum _ { i = 1 } ^ { n } \frac { 4 i + 2 } { n ^ { 2 } }$