Rewrite the sum as a rational function S(n). $\sum _ { i = 1 } ^ { n } \frac { i ^ { 3 } } { n ^ { 3 } }$
A) $S ( n ) = \frac { n ^ { 2 } + 2 n + 1 } { 4 n ^ { 2 } }$
B) $S ( n ) = \frac { n ^ { 2 } + 2 n + 1 } { 4 n ^ { 4 } }$
C) $S ( n ) = \frac { n ^ { 2 } + 2 n + 1 } { 4 n ^ { 5 } }$
D) $S ( n ) = \frac { n ^ { 2 } + 2 n + 1 } { 4 n ^ { 3 } }$
E) $S ( n ) = \frac { n ^ { 2 } + 2 n + 1 } { 4 n }$

Question

Rewrite the sum as a rational function S(n).  $\sum _ { i = 1 } ^ { n } \frac { i ^ { 3 } } { n ^ { 3 } }$  
A) $S ( n ) = \frac { n ^ { 2 } + 2 n + 1 } { 4 n ^ { 2 } }$
B) $S ( n ) = \frac { n ^ { 2 } + 2 n + 1 } { 4 n ^ { 4 } }$
C) $S ( n ) = \frac { n ^ { 2 } + 2 n + 1 } { 4 n ^ { 5 } }$
D) $S ( n ) = \frac { n ^ { 2 } + 2 n + 1 } { 4 n ^ { 3 } }$
E) $S ( n ) = \frac { n ^ { 2 } + 2 n + 1 } { 4 n }$

Quizplus · Accepted Answer

The Answer of Rewrite the sum as a rational function S(n).  $\sum _ { i = 1 } ^ { n } \frac { i ^ { 3 } } { n ^ { 3 } }$  
A) $S ( n ) = \frac { n ^ { 2 } + 2 n + 1 } { 4 n ^ { 2 } }$
B) $S ( n ) = \frac { n ^ { 2 } + 2 n + 1 } { 4 n ^ { 4 } }$
C) $S ( n ) = \frac { n ^ { 2 } + 2 n + 1 } { 4 n ^ { 5 } }$
D) $S ( n ) = \frac { n ^ { 2 } + 2 n + 1 } { 4 n ^ { 3 } }$
E) $S ( n ) = \frac { n ^ { 2 } + 2 n + 1 } { 4 n }$

Rewrite the Sum as a Rational Function S(n) ∑i=1ni3n3\sum _ { i = 1 } ^ { n } \frac { i ^ { 3 } } { n ^ { 3 } }∑i=1n​n3i3​

Rewrite the Sum as a Rational Function S(n) $\sum _ { i = 1 } ^ { n } \frac { i ^ { 3 } } { n ^ { 3 } }$