Find the magnitude of the vector v described below. Initial point: (3,-7,0)
Terminal point: (-1,1,0)
A)-4
B)12
C) $2 \sqrt { 3 }$
D) $8 \sqrt { 5 }$
E) $4 \sqrt { 5 }$

Question

Quizplus · Accepted Answer

The magnitude of a vector given its initial point $(x_1, y_1, z_1)$ and terminal point $(x_2, y_2, z_2)$ can be found using the formula $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2}$. Substituting the given points, we get $\sqrt{(-1 - 3)^2 + (1 - (-7))^2 + (0 - 0)^2} = \sqrt{(-4)^2 + 8^2 + 0} = \sqrt{16 + 64} = \sqrt{80} = 4\sqrt{5}$.

Find the Magnitude of the Vector V Described Below 232 \sqrt { 3 }23​

Find the Magnitude of the Vector V Described Below $2 \sqrt { 3 }$