The vector v and its initial point are given.Find the terminal point. $\mathbf { v } = \left( \frac { 9 } { 2 } , - \frac { 1 } { 2 } , 8 \right)$
Initial point: $\left( 7,6 , - \frac { 1 } { 2 } \right)$
A)Terminal point is $\left( \frac { 23 } { 2 } , \frac { 11 } { 2 } , \frac { 15 } { 2 } \right)$ .
B)Terminal point is $\left( \frac { 23 } { 2 } , \frac { 15 } { 2 } , \frac { 11 } { 2 } \right)$ .
C)Terminal point is $\left( \frac { 11 } { 2 } , \frac { 23 } { 2 } , \frac { 15 } { 2 } \right)$ .
D)Terminal point is $\left( \frac { 11 } { 2 } , \frac { 15 } { 2 } , \frac { 23 } { 2 } \right)$ .
E)Terminal point is $\left( \frac { 15 } { 2 } , \frac { 11 } { 2 } , \frac { 23 } { 2 } \right)$ .

Question

The vector v and its initial point are given.Find the terminal point.  $\mathbf { v } = \left( \frac { 9 } { 2 } , - \frac { 1 } { 2 } , 8 \right)$
Initial point: $\left( 7,6 , - \frac { 1 } { 2 } \right)$ 
A)Terminal point is $\left( \frac { 23 } { 2 } , \frac { 11 } { 2 } , \frac { 15 } { 2 } \right)$ .
B)Terminal point is $\left( \frac { 23 } { 2 } , \frac { 15 } { 2 } , \frac { 11 } { 2 } \right)$ .
C)Terminal point is $\left( \frac { 11 } { 2 } , \frac { 23 } { 2 } , \frac { 15 } { 2 } \right)$ .
D)Terminal point is $\left( \frac { 11 } { 2 } , \frac { 15 } { 2 } , \frac { 23 } { 2 } \right)$ .
E)Terminal point is $\left( \frac { 15 } { 2 } , \frac { 11 } { 2 } , \frac { 23 } { 2 } \right)$ .

Quizplus · Accepted Answer

To find the terminal point, add the vector $\mathbf{v} = \left( \frac{9}{2}, -\frac{1}{2}, 8 \right)$ to the initial point $\left( 7, 6, -\frac{1}{2} \right)$. This results in $\left( 7 + \frac{9}{2}, 6 - \frac{1}{2}, -\frac{1}{2} + 8 \right) = \left( \frac{23}{2}, \frac{11}{2}, \frac{15}{2} \right)$.

The Vector V and Its Initial Point Are Given v=(92,−12,8)\mathbf { v } = \left( \frac { 9 } { 2 } , - \frac { 1 } { 2 } , 8 \right)v=(29​,−21​,8)

The Vector V and Its Initial Point Are Given $\mathbf { v } = \left( \frac { 9 } { 2 } , - \frac { 1 } { 2 } , 8 \right)$