Find the general form of the equation of the plane passing through the point and perpendicular to the specified line.[Be sure to reduce the coefficients in your answer to lowest terms by dividing out any common factor.] $\begin{array} { l }
( - 7 , - 8 , - 1 ) \
x = 3 + 2 t \
y = - 3 - 2 t \
z = 2 + 4 t
\end{array}$
A)7x + 8y + z + 2 = 0
B)7x + 8y + z - 2 = 0
C)x - y + 2z - 1 = 0
D)x - y + 2z + 1 = 0
E)x - y + 2z = 0

Question

Find the general form of the equation of the plane passing through the point and perpendicular to the specified line.[Be sure to reduce the coefficients in your answer to lowest terms by dividing out any common factor.] $\begin{array} { l } 
( - 7 , - 8 , - 1 ) \
x = 3 + 2 t \
y = - 3 - 2 t \
z = 2 + 4 t
\end{array}$
A)7x + 8y + z + 2 = 0
B)7x + 8y + z - 2 = 0
C)x - y + 2z - 1 = 0
D)x - y + 2z + 1 = 0
E)x - y + 2z = 0

Quizplus · Accepted Answer

The Answer of Find the general form of the equation of the plane passing through the point and perpendicular to the specified line.[Be sure to reduce the coefficients in your answer to lowest terms by dividing out any common factor.] $\begin{array} { l } 
( - 7 , - 8 , - 1 ) \
x = 3 + 2 t \
y = - 3 - 2 t \
z = 2 + 4 t
\end{array}$
A)7x + 8y + z + 2 = 0
B)7x + 8y + z - 2 = 0
C)x - y + 2z - 1 = 0
D)x - y + 2z + 1 = 0
E)x - y + 2z = 0

Find the General Form of the Equation of the Plane (−7,−8,−1)x=3+2ty=−3−2tz=2+4t\begin{array} { l } ( - 7 , - 8 , - 1 ) \\x = 3 + 2 t \\y = - 3 - 2 t \\z = 2 + 4 t\end{array}(−7,−8,−1)x=3+2ty=−3−2tz=2+4t​

Find the General Form of the Equation of the Plane $\begin{array} { l } ( - 7 , - 8 , - 1 ) \\x = 3 + 2 t \\y = - 3 - 2 t \\z = 2 + 4 t\end{array}$