Find the general form of the equation of the plane passing through the point and perpendicular to the specified vector or line.
Point: $( 0,0,8 )$ Perpendicular to: $x = 1 - t , y = 2 + t , z = 4 - 4 t$
A) $x - y + 4 z - 32 = 0$
B) $x + y - 4 z - 32 = 0$
C) $- x - y - 4 z + 32 = 0$
D) $- x + y + 4 z + 32 = 0$
E) $- x + y - 4 z + 32 = 0$

Question

Find the general form of the equation of the plane passing through the point and perpendicular to the specified vector or line. 
Point: $( 0,0,8 )$ Perpendicular to: $x = 1 - t , y = 2 + t , z = 4 - 4 t$ 
A) $x - y + 4 z - 32 = 0$
B) $x + y - 4 z - 32 = 0$
C) $- x - y - 4 z + 32 = 0$
D) $- x + y + 4 z + 32 = 0$
E) $- x + y - 4 z + 32 = 0$

Quizplus · Accepted Answer

The Answer of Find the general form of the equation of the plane passing through the point and perpendicular to the specified vector or line. 
Point: $( 0,0,8 )$ Perpendicular to: $x = 1 - t , y = 2 + t , z = 4 - 4 t$ 
A) $x - y + 4 z - 32 = 0$
B) $x + y - 4 z - 32 = 0$
C) $- x - y - 4 z + 32 = 0$
D) $- x + y + 4 z + 32 = 0$
E) $- x + y - 4 z + 32 = 0$

Find the General Form of the Equation of the Plane (0,0,8)( 0,0,8 )(0,0,8)

Find the General Form of the Equation of the Plane $( 0,0,8 )$