Find the angle $\theta$ (in radians and degrees) between the lines.Round your answer to four decimal places for radians and round your answer to one decimal places for degree. $\begin{array} { l }
x - y = 10 \
3 x - 2 y = 1
\end{array}$
A) $\Theta \approx 0.0907 \text { radians } \approx 6.2 ^ { \circ }$
B) $\Theta \approx 0.0907 \text { radians } \approx 4.2 ^ { \circ }$
C) $\Theta \approx 0.0907 \text { radians } \approx 5.2 ^ { \circ }$
D) $\Theta \approx 0.0907 \text { radians } \approx 7.2 ^ { \circ }$
E) $\Theta \approx 0.0907 \text { radians } \approx 3.2 ^ { \circ }$

Question

Find the angle $\theta$ (in radians and degrees) between the lines.Round your answer to four decimal places for radians and round your answer to one decimal places for degree.  $\begin{array} { l } 
x - y = 10 \
3 x - 2 y = 1
\end{array}$ 
A) $\Theta \approx 0.0907 \text { radians } \approx 6.2 ^ { \circ }$
B) $\Theta \approx 0.0907 \text { radians } \approx 4.2 ^ { \circ }$
C) $\Theta \approx 0.0907 \text { radians } \approx 5.2 ^ { \circ }$
D) $\Theta \approx 0.0907 \text { radians } \approx 7.2 ^ { \circ }$
E) $\Theta \approx 0.0907 \text { radians } \approx 3.2 ^ { \circ }$

Quizplus · Accepted Answer

The slopes of the lines are 1 and 1.5. The angle $\theta$ between them is given by $\tan^{-1}(|\frac{1.5-1}{1+1.5 \cdot 1}|)$, which is approximately 0.0907 radians or 5.2 degrees.

Find the Angle θ\thetaθ (In Radians and Degrees) Between the Lines x−y=103x−2y=1\begin{array} { l } x - y = 10 \\3 x - 2 y = 1\end{array}x−y=103x−2y=1​

Find the Angle $\theta$ (In Radians and Degrees) Between the Lines $\begin{array} { l } x - y = 10 \\3 x - 2 y = 1\end{array}$