Find the standard form of the equation of the parabola and determine the coordinates of the focus.
A) $x ^ { 2 } = \frac { 1 } { 9 } y$ focus: $\left( 0 , \frac { 1 } { 36 } \right)$
B) $x ^ { 2 } = - \frac { 1 } { 36 } y$ focus: $\left( 0 , - \frac { 1 } { 36 } \right)$
C) $x ^ { 2 } = \frac { 1 } { 9 } y$ focus: $\left( 0 , - \frac { 1 } { 9 } \right)$
D) $x ^ { 2 } = 9 y$ focus: $\left( 0 , - \frac { 1 } { 9 } \right)$
E) $x ^ { 2 } = - 9 y$ focus: (0, 4)

Question

Find the standard form of the equation of the parabola and determine the coordinates of the focus. 
A) $x ^ { 2 } = \frac { 1 } { 9 } y$ focus: $\left( 0 , \frac { 1 } { 36 } \right)$ 
B) $x ^ { 2 } = - \frac { 1 } { 36 } y$ focus: $\left( 0 , - \frac { 1 } { 36 } \right)$ 
C) $x ^ { 2 } = \frac { 1 } { 9 } y$ focus: $\left( 0 , - \frac { 1 } { 9 } \right)$ 
D) $x ^ { 2 } = 9 y$ focus: $\left( 0 , - \frac { 1 } { 9 } \right)$ 
E) $x ^ { 2 } = - 9 y$ focus: (0, 4)

Quizplus · Accepted Answer

The Answer of Find the standard form of the equation of the parabola and determine the coordinates of the focus. 
A) $x ^ { 2 } = \frac { 1 } { 9 } y$ focus: $\left( 0 , \frac { 1 } { 36 } \right)$ 
B) $x ^ { 2 } = - \frac { 1 } { 36 } y$ focus: $\left( 0 , - \frac { 1 } { 36 } \right)$ 
C) $x ^ { 2 } = \frac { 1 } { 9 } y$ focus: $\left( 0 , - \frac { 1 } { 9 } \right)$ 
D) $x ^ { 2 } = 9 y$ focus: $\left( 0 , - \frac { 1 } { 9 } \right)$ 
E) $x ^ { 2 } = - 9 y$ focus: (0, 4)

Find the Standard Form of the Equation of the Parabola x2=19yx ^ { 2 } = \frac { 1 } { 9 } yx2=91​y

Find the Standard Form of the Equation of the Parabola $x ^ { 2 } = \frac { 1 } { 9 } y$