Find the standard form of the equation of the parabola with the given characteristic(s) and vertex at the origin.
Focus: (-4,0)

A) $y ^ { 2 } = - 16 x$
B) $y ^ { 2 } = 16 x$
C) $x ^ { 2 } = - 16 y$
D) $x ^ { 2 } = - 16 y$.
E) $y ^ { 2 } = - \frac { x } { 16 }$

Question

Find the standard form of the equation of the parabola with the given characteristic(s) and vertex at the origin. 
Focus: (-4,0)

A) $y ^ { 2 } = - 16 x$
B) $y ^ { 2 } = 16 x$
C) $x ^ { 2 } = - 16 y$
D) $x ^ { 2 } = - 16 y$.
E) $y ^ { 2 } = - \frac { x } { 16 }$

Quizplus · Accepted Answer

The focus of the parabola is at (-4,0), indicating that the parabola opens to the left. The standard form for a parabola opening to the left or right is $y^2 = 4px$, where $p$ is the distance from the vertex to the focus. Here, $p = -4$, so the equation becomes $y^2 = -16x$.

Find the Standard Form of the Equation of the Parabola y2=−16xy ^ { 2 } = - 16 xy2=−16x

Find the Standard Form of the Equation of the Parabola $y ^ { 2 } = - 16 x$