Identify the conic as a circle or an ellipse then find the center. $\frac { x ^ { 2 } } { 49 } + \frac { y ^ { 2 } } { 49 } = 1$
A)CircleCenter: (0,0)
B)EllipseCenter: (0,0)
C)CircleCenter: (7,0)
D)EllipseCenter: (0,7)
E)CircleCenter: (7,7)

Question

Identify the conic as a circle or an ellipse then find the center.  $\frac { x ^ { 2 } } { 49 } + \frac { y ^ { 2 } } { 49 } = 1$ 
A)CircleCenter: (0,0)
B)EllipseCenter: (0,0)
C)CircleCenter: (7,0)
D)EllipseCenter: (0,7)
E)CircleCenter: (7,7)

Quizplus · Accepted Answer

The equation is in the form $\frac{x^2}{a^2} + \frac{y^2}{a^2} = 1$ with $a^2 = 49$, indicating a circle (since the coefficients of $x^2$ and $y^2$ are equal) with a center at (0,0).

Identify the Conic as a Circle or an Ellipse Then x249+y249=1\frac { x ^ { 2 } } { 49 } + \frac { y ^ { 2 } } { 49 } = 149x2​+49y2​=1

Identify the Conic as a Circle or an Ellipse Then $\frac { x ^ { 2 } } { 49 } + \frac { y ^ { 2 } } { 49 } = 1$