Find the center and vertices of the hyperbola. $12 x ^ { 2 } - 4 y ^ { 2 } - 48 x + 32 y - 64 = 0$
A)center: (-2, -4), vertices: (-2, -6), (-2, -2)
B)center: (2, 4), vertices: (2, 2), (2, 6)
C)center: (2, 4), vertices: (0, 4), (4, 4)
D)center: (-2, -4), vertices: (-4, -4), (0, -4)
E)center: (-4, -2), vertices: (-6, -2), (-2, -2)

Question

Quizplus · Accepted Answer

The Answer of Find the center and vertices of the hyperbola. $12 x ^ { 2 } - 4 y ^ { 2 } - 48 x + 32 y - 64 = 0$
A)center: (-2, -4), vertices: (-2, -6), (-2, -2)
B)center: (2, 4), vertices: (2, 2), (2, 6)
C)center: (2, 4), vertices: (0, 4), (4, 4)
D)center: (-2, -4), vertices: (-4, -4), (0, -4)
E)center: (-4, -2), vertices: (-6, -2), (-2, -2)

Find the Center and Vertices of the Hyperbola 12x2−4y2−48x+32y−64=012 x ^ { 2 } - 4 y ^ { 2 } - 48 x + 32 y - 64 = 012x2−4y2−48x+32y−64=0

Find the Center and Vertices of the Hyperbola $12 x ^ { 2 } - 4 y ^ { 2 } - 48 x + 32 y - 64 = 0$