Find the center, vertices and foci of the hyperbola. $21 x ^ { 2 } - 5 y ^ { 2 } = 105$
A)Center: (0, 0)Vertices: (0, 0)Foci: $( \sqrt { 21 } , 0 )$
B)Center: (0, 0)Vertices: $( 0 , \pm \sqrt { 5 } )$ Foci: $( \pm \sqrt { 26 } , 0 )$
C)Center: (0, 0)Vertices: $( \pm \sqrt { 5 } , 0 )$ Foci: $( \pm \sqrt { 26 } , 0 )$
D)Center: (0, 0)Vertices: $( - \sqrt { 5 } , 0 )$ Foci: $( \pm \sqrt { 26 } , 0 )$
E)Center: (0, 0)Vertices: $( 0 , \pm \sqrt { 5 } )$ Foci: $( 0 , \pm \sqrt { 26 } )$

Question

Find the center, vertices and foci of the hyperbola.  $21 x ^ { 2 } - 5 y ^ { 2 } = 105$ 
A)Center: (0, 0)Vertices: (0, 0)Foci: $( \sqrt { 21 } , 0 )$
B)Center: (0, 0)Vertices: $( 0 , \pm \sqrt { 5 } )$ Foci: $( \pm \sqrt { 26 } , 0 )$
C)Center: (0, 0)Vertices: $( \pm \sqrt { 5 } , 0 )$ Foci: $( \pm \sqrt { 26 } , 0 )$
D)Center: (0, 0)Vertices: $( - \sqrt { 5 } , 0 )$ Foci: $( \pm \sqrt { 26 } , 0 )$
E)Center: (0, 0)Vertices: $( 0 , \pm \sqrt { 5 } )$ Foci: $( 0 , \pm \sqrt { 26 } )$

Quizplus · Accepted Answer

The given equation can be rewritten as $\frac{x^2}{5} - \frac{y^2}{21} = 1$, which is a hyperbola centered at (0,0) with vertices at $(\pm \sqrt{5}, 0)$ and foci at $(\pm \sqrt{26}, 0)$.

Find the Center, Vertices and Foci of the Hyperbola 21x2−5y2=10521 x ^ { 2 } - 5 y ^ { 2 } = 10521x2−5y2=105

Find the Center, Vertices and Foci of the Hyperbola $21 x ^ { 2 } - 5 y ^ { 2 } = 105$