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By Using a Graphing Utility Select the Correct Graph of the Polar

Question 32

Multiple Choice

By using a graphing utility select the correct graph of the polar equation.Identify the graph. 1313+16sin⁡θ\frac { 13 } { 13 + 16 \sin \theta }


A) By using a graphing utility select the correct graph of the polar equation.Identify the graph. \frac { 13 } { 13 + 16 \sin \theta } A) e = \frac { 16 } { 13 } > 1 \Rightarrow Hyperbola B) e = \frac { 16 } { 13 } > 1 \Rightarrow Hyperbola C) e = \frac { 16 } { 13 } > 1 \Rightarrow Hyperbola D) e = \frac { 16 } { 13 } > 1 \Rightarrow Hyperbola E) e = \frac { 16 } { 13 } > 1 \Rightarrow Hyperbola e=e = 1613\frac { 16 } { 13 } >1⇒> 1 \Rightarrow Hyperbola
B) By using a graphing utility select the correct graph of the polar equation.Identify the graph. \frac { 13 } { 13 + 16 \sin \theta } A) e = \frac { 16 } { 13 } > 1 \Rightarrow Hyperbola B) e = \frac { 16 } { 13 } > 1 \Rightarrow Hyperbola C) e = \frac { 16 } { 13 } > 1 \Rightarrow Hyperbola D) e = \frac { 16 } { 13 } > 1 \Rightarrow Hyperbola E) e = \frac { 16 } { 13 } > 1 \Rightarrow Hyperbola e=e = 1613\frac { 16 } { 13 } >1⇒> 1 \Rightarrow Hyperbola
C) By using a graphing utility select the correct graph of the polar equation.Identify the graph. \frac { 13 } { 13 + 16 \sin \theta } A) e = \frac { 16 } { 13 } > 1 \Rightarrow Hyperbola B) e = \frac { 16 } { 13 } > 1 \Rightarrow Hyperbola C) e = \frac { 16 } { 13 } > 1 \Rightarrow Hyperbola D) e = \frac { 16 } { 13 } > 1 \Rightarrow Hyperbola E) e = \frac { 16 } { 13 } > 1 \Rightarrow Hyperbola e=e = 1613\frac { 16 } { 13 } >1⇒> 1 \Rightarrow Hyperbola
D) By using a graphing utility select the correct graph of the polar equation.Identify the graph. \frac { 13 } { 13 + 16 \sin \theta } A) e = \frac { 16 } { 13 } > 1 \Rightarrow Hyperbola B) e = \frac { 16 } { 13 } > 1 \Rightarrow Hyperbola C) e = \frac { 16 } { 13 } > 1 \Rightarrow Hyperbola D) e = \frac { 16 } { 13 } > 1 \Rightarrow Hyperbola E) e = \frac { 16 } { 13 } > 1 \Rightarrow Hyperbola e=e = 1613\frac { 16 } { 13 } >1⇒> 1 \Rightarrow Hyperbola
E) By using a graphing utility select the correct graph of the polar equation.Identify the graph. \frac { 13 } { 13 + 16 \sin \theta } A) e = \frac { 16 } { 13 } > 1 \Rightarrow Hyperbola B) e = \frac { 16 } { 13 } > 1 \Rightarrow Hyperbola C) e = \frac { 16 } { 13 } > 1 \Rightarrow Hyperbola D) e = \frac { 16 } { 13 } > 1 \Rightarrow Hyperbola E) e = \frac { 16 } { 13 } > 1 \Rightarrow Hyperbola e=e = 1613\frac { 16 } { 13 } >1⇒> 1 \Rightarrow Hyperbola

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