Select the first five terms of the sequence. $a _ { n } = 2 - \frac { 1 } { 5 ^ { n } }$
A) $\frac { 9 } { 125 } , \frac { 49 } { 25 } , \frac { 249 } { 5 } , \frac { 1249 } { 25 } , \frac { 6249 } { 125 }$
B) $\frac { 9 } { 25 } , \frac { 49 } { 125 } , \frac { 249 } { 625 } , \frac { 1249 } { 3125 } , \frac { 6249 } { 5 }$
C) $\frac { 5 } { 9 } , \frac { 25 } { 49 } , \frac { 125 } { 249 } , \frac { 625 } { 1249 } , \frac { 3125 } { 6249 }$
D) $\frac { 49 } { 5 } , \frac { 249 } { 25 } , \frac { 1249 } { 125 } , \frac { 6249 } { 625 } , \frac { 9 } { 3125 }$
E) $\frac { 9 } { 5 } , \frac { 49 } { 25 } , \frac { 249 } { 125 } , \frac { 1249 } { 625 } , \frac { 6249 } { 3125 }$

Question

Select the first five terms of the sequence.  $a _ { n } = 2 - \frac { 1 } { 5 ^ { n } }$  
A) $\frac { 9 } { 125 } , \frac { 49 } { 25 } , \frac { 249 } { 5 } , \frac { 1249 } { 25 } , \frac { 6249 } { 125 }$
B) $\frac { 9 } { 25 } , \frac { 49 } { 125 } , \frac { 249 } { 625 } , \frac { 1249 } { 3125 } , \frac { 6249 } { 5 }$
C) $\frac { 5 } { 9 } , \frac { 25 } { 49 } , \frac { 125 } { 249 } , \frac { 625 } { 1249 } , \frac { 3125 } { 6249 }$
D) $\frac { 49 } { 5 } , \frac { 249 } { 25 } , \frac { 1249 } { 125 } , \frac { 6249 } { 625 } , \frac { 9 } { 3125 }$
E) $\frac { 9 } { 5 } , \frac { 49 } { 25 } , \frac { 249 } { 125 } , \frac { 1249 } { 625 } , \frac { 6249 } { 3125 }$

Quizplus · Accepted Answer

To find the first five terms of the sequence $a_n = 2 - \frac{1}{5^n}$, we substitute $n = 1, 2, 3, 4, 5$ into the formula. For $n=1$, $a_1 = 2 - \frac{1}{5} = \frac{9}{5}$. For $n=2$, $a_2 = 2 - \frac{1}{25} = \frac{49}{25}$, and so on, leading to the sequence in option E.

Select the First Five Terms of the Sequence an=2−15na _ { n } = 2 - \frac { 1 } { 5 ^ { n } }an​=2−5n1​

Select the First Five Terms of the Sequence $a _ { n } = 2 - \frac { 1 } { 5 ^ { n } }$