Find the coefficient a of the term in the expansion of the binomial. $\begin{array}{lr}\text { Binominal }&\text { Terms }\
(x+7)^{12} & a x^{5}
\end{array}$

A)-407,653,785
B)-652,246,056
C)760,953,732
D)181,179,460
E)652,246,056

Question

Find the coefficient a of the term in the expansion of the binomial.  $\begin{array}{lr}\text { Binominal }&\text { Terms }\
(x+7)^{12} & a x^{5}
\end{array}$

A)-407,653,785
B)-652,246,056
C)760,953,732
D)181,179,460
E)652,246,056

Quizplus · Accepted Answer

The coefficient $a$ of the term $x^5$ in the expansion of $(x+7)^{12}$ can be found using the binomial theorem, specifically the term is given by $\binom{12}{5}x^5(7)^{12-5}$. Calculating this gives $\binom{12}{5} \cdot 7^7 = 792 \cdot 823543 = 652,246,056$.

Find the Coefficient a of the Term in the Expansion Binominal Terms (x+7)12ax5\begin{array}{lr}\text { Binominal }&\text { Terms }\\(x+7)^{12} & a x^{5}\end{array} Binominal (x+7)12​ Terms ax5​

Find the Coefficient a of the Term in the Expansion $\begin{array}{lr}\text { Binominal }&\text { Terms }\\(x+7)^{12} & a x^{5}\end{array}$