Solve the system using Gauss-Jordan elimination. $$\left\{ \begin{aligned}
x + y + 2 z + t & = 62 \
x + 2 y + z + t & = 62 \
2 x + y + z + t & = 49 \
x + y + z + 2 t & = 62
\end{aligned} \right.$$
A) $( 2 , - 15,15 , - 15 )$
B) $( - 2,15,15,15 )$
C) $( 2 , - 15,15,15 )$
D) $( 2,15,15,15 )$
E) $( 2,15 , - 15,15 )$

Question

Solve the system using Gauss-Jordan elimination.   $$\left\{ \begin{aligned}
x + y + 2 z + t & = 62 \
x + 2 y + z + t & = 62 \
2 x + y + z + t & = 49 \
x + y + z + 2 t & = 62
\end{aligned} \right.$$  
A) $( 2 , - 15,15 , - 15 )$  
B) $( - 2,15,15,15 )$  
C) $( 2 , - 15,15,15 )$  
D) $( 2,15,15,15 )$  
E) $( 2,15 , - 15,15 )$

Quizplus · Accepted Answer

The Answer of Solve the system using Gauss-Jordan elimination.   $$\left\{ \begin{aligned}
x + y + 2 z + t & = 62 \
x + 2 y + z + t & = 62 \
2 x + y + z + t & = 49 \
x + y + z + 2 t & = 62
\end{aligned} \right.$$  
A) $( 2 , - 15,15 , - 15 )$  
B) $( - 2,15,15,15 )$  
C) $( 2 , - 15,15,15 )$  
D) $( 2,15,15,15 )$  
E) $( 2,15 , - 15,15 )$

Solve the System Using Gauss-Jordan Elimination {x+y+2z+t=62x+2y+z+t=622x+y+z+t=49x+y+z+2t=62\left\{ \begin{aligned}x + y + 2 z + t & = 62 \\x + 2 y + z + t & = 62 \\2 x + y + z + t & = 49 \\x + y + z + 2 t & = 62\end{aligned} \right.⎩⎨⎧​x+y+2z+tx+2y+z+t2x+y+z+tx+y+z+2t​=62=62=49=62​

Solve the System Using Gauss-Jordan Elimination $\left\{ \begin{aligned}x + y + 2 z + t & = 62 \\x + 2 y + z + t & = 62 \\2 x + y + z + t & = 49 \\x + y + z + 2 t & = 62\end{aligned} \right.$