Find the system of linear equations represented by the augmented matrix.Then use back substitution to solve.(Use variables x, y, z, and w if applicable.) $$\left[ \begin{array} { c c c c }
1 & 7 & \vdots & 0 \
0 & 1 & \vdots & - 1
\end{array} \right]$$
A) $\left\{ \begin{array} { r }
x + 7 y = 0 \
y = 0
\end{array} \right.$ (7, 0)
B) $\left\{ \begin{aligned}
x + 7 y & = 0 \
x & = - 1
\end{aligned} \right.$ (-1, 7)
C) $\left\{ \begin{aligned}
x + 7 y & = 0 \
y & = - 1
\end{aligned} \right.$ (7, -1)
D) $\left\{ \begin{array} { r }
x + 7 y = 0 \
y = 1
\end{array} \right.$ (7, 1)
E) $\left\{ \begin{aligned}
x + 7 y & = 0 \
y & = - 1
\end{aligned} \right.$ (7, 1)

Question

Find the system of linear equations represented by the augmented matrix.Then use back substitution to solve.(Use variables x, y, z, and w if applicable.)   $$\left[ \begin{array} { c c c c } 
1 & 7 & \vdots & 0 \
0 & 1 & \vdots & - 1
\end{array} \right]$$  
A)  $\left\{ \begin{array} { r } 
x + 7 y = 0 \
y = 0
\end{array} \right.$ (7, 0)
B)  $\left\{ \begin{aligned}
x + 7 y & = 0 \
x & = - 1
\end{aligned} \right.$  (-1, 7)
C)  $\left\{ \begin{aligned}
x + 7 y & = 0 \
y & = - 1
\end{aligned} \right.$  (7, -1)
D)  $\left\{ \begin{array} { r } 
x + 7 y = 0 \
y = 1
\end{array} \right.$  (7, 1)
E)  $\left\{ \begin{aligned}
x + 7 y & = 0 \
y & = - 1
\end{aligned} \right.$  (7, 1)

Quizplus · Accepted Answer

The augmented matrix directly translates to the system of equations: $x + 7y = 0$ and $y = -1$. Solving the second equation gives $y = -1$, and substituting $y = -1$ into the first equation gives $x + 7(-1) = 0$, which simplifies to $x = 7$. Therefore, the solution is $x = 7, y = -1$.

Find the System of Linear Equations Represented by the Augmented [17⋮001⋮−1]\left[ \begin{array} { c c c c } 1 & 7 & \vdots & 0 \\0 & 1 & \vdots & - 1\end{array} \right]​10​71​⋮⋮​0−1​​

Find the System of Linear Equations Represented by the Augmented $\left[ \begin{array} { c c c c } 1 & 7 & \vdots & 0 \\0 & 1 & \vdots & - 1\end{array} \right]$