Use an inverse matrix to solve (if possible) the system of linear equations. $\left\{ \begin{array} { l l }
1.8 x - 5 y & = 4 \
28.8 x - 16 y & = 5
\end{array} \right.$
A) ( $\frac { 1 } { 16 }$ , 16)
B) (0, 0)
C) ( $\frac { 1 } { 16 }$ , $\frac { 5 } { 16 }$ )
D) (16, 16)
E) No solution

Question

Use an inverse matrix to solve (if possible) the system of linear equations.   $\left\{ \begin{array} { l l } 
1.8 x - 5 y & = 4 \
28.8 x - 16 y & = 5
\end{array} \right.$  
A) ( $\frac { 1 } { 16 }$ , 16)
B) (0, 0)
C) ( $\frac { 1 } { 16 }$ , $\frac { 5 } { 16 }$ )
D) (16, 16)
E) No solution

Quizplus · Accepted Answer

The determinant of the coefficient matrix is zero, indicating that the matrix is singular and does not have an inverse, so the system has no unique solution.

Use an Inverse Matrix to Solve (If Possible) the System {1.8x−5y=428.8x−16y=5\left\{ \begin{array} { l l } 1.8 x - 5 y & = 4 \\28.8 x - 16 y & = 5\end{array} \right.{1.8x−5y28.8x−16y​=4=5​

Use an Inverse Matrix to Solve (If Possible) the System $\left\{ \begin{array} { l l } 1.8 x - 5 y & = 4 \\28.8 x - 16 y & = 5\end{array} \right.$