Solve the system of linear equations.
$\left\{ \begin{array} { l }
x - 2 y = 0 \
2 x - 3 y = 8
\end{array} \right.$
A) $( 16,8 )$
B) $( 16 , - 8 )$
C) $( - 8,16 )$
D) $( 8,16 )$
E) $( - 16,8 )$

Question

Solve the system of linear equations.  
 $\left\{ \begin{array} { l } 
x - 2 y = 0 \
2 x - 3 y = 8
\end{array} \right.$  
A)  $( 16,8 )$
B)  $( 16 , - 8 )$
C)  $( - 8,16 )$
D)  $( 8,16 )$
E)  $( - 16,8 )$

Quizplus · Accepted Answer

Explanation:Multiply the first equation by 2 to get 2x - 4y = 0. Add this to the second equation to get -y = 8, so y = -8. Substitute this into the first equation to get x = 16. Therefore, the solution is (16, -8).

Solve the System of Linear Equations {x−2y=02x−3y=8\left\{ \begin{array} { l } x - 2 y = 0 \\2 x - 3 y = 8\end{array} \right.{x−2y=02x−3y=8​

Solve the System of Linear Equations $\left\{ \begin{array} { l } x - 2 y = 0 \\2 x - 3 y = 8\end{array} \right.$