Find the determinant of $\left[ \begin{array} { c c c }
0 & 1 & 1 \
2 & - 2 & 0 \
- 1 & - 8 & - 3
\end{array} \right]$ .
A)8
B)-10
C)-15
D)-12
E)2

Question

Find the determinant of $\left[ \begin{array} { c c c } 
0 & 1 & 1 \
2 & - 2 & 0 \
- 1 & - 8 & - 3
\end{array} \right]$ .
A)8
B)-10
C)-15
D)-12
E)2

Quizplus · Accepted Answer

The determinant of the matrix can be calculated using the formula for a 3x3 matrix: $\text{det}(A) = a(ei - fh) - b(di - fg) + c(dh - eg)$. Substituting the values from the given matrix, we get $\text{det}(A) = 0((-2)(-3) - (0)(-8)) - 1((2)(-3) - (-1)(0)) + 1((2)(-8) - (-1)(-2)) = 0 - (-6) + (-16 + 2) = -6 - 14 = -12$.

Find the Determinant Of [0112−20−1−8−3]\left[ \begin{array} { c c c } 0 & 1 & 1 \\2 & - 2 & 0 \\- 1 & - 8 & - 3\end{array} \right]​02−1​1−2−8​10−3​​

Find the Determinant Of $\left[ \begin{array} { c c c } 0 & 1 & 1 \\2 & - 2 & 0 \\- 1 & - 8 & - 3\end{array} \right]$