Find the dimensions of the rectangle meeting the specified condition.
The perimeter is 528 feet and the length is $4 \frac { 1 } { 2 }$ times the width.

A)216 ft × 52 ft
B)216 ft × 48 ft
C)220 ft × 52 ft
D)218 ft × 48 ft
E)218 ft × 50 ft

Question

Find the dimensions of the rectangle meeting the specified condition.  
The perimeter is 528 feet and the length is $4 \frac { 1 } { 2 }$ times the width.
 
A)216 ft × 52 ft
B)216 ft × 48 ft
C)220 ft × 52 ft
D)218 ft × 48 ft
E)218 ft × 50 ft

Quizplus · Accepted Answer

Let the width be $ w $. Then the length is $ 4.5w $. The perimeter is given by $ 2(w + 4.5w) = 528 $. Solving for $ w $, we get $ w = 48 $ ft and the length $ 4.5 \times 48 = 216 $ ft. Thus, the dimensions are 216 ft × 48 ft.

Find the Dimensions of the Rectangle Meeting the Specified Condition 4124 \frac { 1 } { 2 }421​

Find the Dimensions of the Rectangle Meeting the Specified Condition $4 \frac { 1 } { 2 }$