Solve the system by the method of substitution. $\left\{ \begin{array} { l }
2 x - y + 2 = 0 \
4 x + y - 5 = 0
\end{array} \right.$
A) $\left( \frac { 1 } { 2 } , - 3 \right)$
B)(1, 3)
C) $\left( - \frac { 1 } { 2 } , 3 \right)$
D) $\left( \frac { 1 } { 2 } , 3 \right)$
E)(-1, 3)

Question

Solve the system by the method of substitution.  $\left\{ \begin{array} { l } 
2 x - y + 2 = 0 \
4 x + y - 5 = 0
\end{array} \right.$  
A) $\left( \frac { 1 } { 2 } , - 3 \right)$
B)(1, 3)
C) $\left( - \frac { 1 } { 2 } , 3 \right)$
D) $\left( \frac { 1 } { 2 } , 3 \right)$
E)(-1, 3)

Quizplus · Accepted Answer

The Answer of Solve the system by the method of substitution.  $\left\{ \begin{array} { l } 
2 x - y + 2 = 0 \
4 x + y - 5 = 0
\end{array} \right.$  
A) $\left( \frac { 1 } { 2 } , - 3 \right)$
B)(1, 3)
C) $\left( - \frac { 1 } { 2 } , 3 \right)$
D) $\left( \frac { 1 } { 2 } , 3 \right)$
E)(-1, 3)

Solve the System by the Method of Substitution {2x−y+2=04x+y−5=0\left\{ \begin{array} { l } 2 x - y + 2 = 0 \\4 x + y - 5 = 0\end{array} \right.{2x−y+2=04x+y−5=0​

Solve the System by the Method of Substitution $\left\{ \begin{array} { l } 2 x - y + 2 = 0 \\4 x + y - 5 = 0\end{array} \right.$