Solve the system by the method of elimination and check any solutions algebraically. $\left\{ \begin{array} { l }
0.05 x - 0.03 y = 0.29 \
0.07 x + 0.02 y = 0.22
\end{array} \right.$
A)(4, - 3)
B)(4, 3)
C) (7, - 7)
D) (- 4, 3)
E) (- 4, - 3)

Question

Solve the system by the method of elimination and check any solutions algebraically.  $\left\{ \begin{array} { l } 
0.05 x - 0.03 y = 0.29 \
0.07 x + 0.02 y = 0.22
\end{array} \right.$  
A)(4, - 3)
B)(4, 3)
C) (7, - 7)
D) (- 4, 3)
E) (- 4, - 3)

Quizplus · Accepted Answer

By multiplying the equations to eliminate y, we find x = 4 and y = -3. Substituting these values back into the original equations confirms they satisfy both equations.

Solve the System by the Method of Elimination and Check {0.05x−0.03y=0.290.07x+0.02y=0.22\left\{ \begin{array} { l } 0.05 x - 0.03 y = 0.29 \\0.07 x + 0.02 y = 0.22\end{array} \right.{0.05x−0.03y=0.290.07x+0.02y=0.22​

Solve the System by the Method of Elimination and Check $\left\{ \begin{array} { l } 0.05 x - 0.03 y = 0.29 \\0.07 x + 0.02 y = 0.22\end{array} \right.$