Sixty liters of a 43% acid solution is obtained by mixing a 28% solution with a 42% solution.Use a graphing utility to graph the two given equations.Let x and y represent the amounts of the 28 % solution and 42% solution.As the amount of the 28% solution increases, how does the amount of the 42% solution change $$\left\{ \begin{array} { l }
x + y = 60 \
0.28 x + 0.42 y = 25.8
\end{array} \right.$$

A) Increases
B) Decreases
C) Decreases
D) Decreases
E) Increases

Question

Sixty liters of a 43% acid solution is obtained by mixing a 28% solution with a 42% solution.Use a graphing utility to graph the two given equations.Let x and y represent the amounts of the 28 % solution and 42% solution.As the amount of the 28% solution increases, how does the amount of the 42% solution change  $$\left\{ \begin{array} { l } 
x + y = 60 \
0.28 x + 0.42 y = 25.8
\end{array} \right.$$  
 
A) Increases 
B) Decreases 
C) Decreases 
D) Decreases 
E) Increases

Quizplus · Accepted Answer

The Answer of Sixty liters of a 43% acid solution is obtained by mixing a 28% solution with a 42% solution.Use a graphing utility to graph the two given equations.Let x and y represent the amounts of the 28 % solution and 42% solution.As the amount of the 28% solution increases, how does the amount of the 42% solution change  $$\left\{ \begin{array} { l } 
x + y = 60 \
0.28 x + 0.42 y = 25.8
\end{array} \right.$$  
 
A) Increases 
B) Decreases 
C) Decreases 
D) Decreases 
E) Increases

Sixty Liters of a 43% Acid Solution Is Obtained by Mixing