Find values for b such that the triangle has two solutions. A = 46°, a = 10 A) $10 \geq b \geq \frac { 10 } { \sin 46 ^ { \circ } }$ B) $10 \leq b \leq \frac { 10 } { \sin 46 ^ { \circ } }$ C) $10 b \frac { 10 } { \sin 46 ^ { \circ } }$ D) $10

Question

Find values for b such that the triangle has two solutions. A = 46°, a = 10 A) $10 \geq b \geq \frac { 10 } { \sin 46 ^ { \circ } }$ B) $10 \leq b \leq \frac { 10 } { \sin 46 ^ { \circ } }$ C) $10 > b > \frac { 10 } { \sin 46 ^ { \circ } }$ D) $10 < b \leq \frac { 10 } { \sin 46 ^ { \circ } }$ E) $10 < b < \frac { 10 } { \sin 46 ^ { \circ } }$

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The Answer of Find values for b such that the triangle has two solutions. A = 46°, a = 10 A) $10 \geq b \geq \frac { 10 } { \sin 46 ^ { \circ } }$ B) $10 \leq b \leq \frac { 10 } { \sin 46 ^ { \circ } }$ C) $10 > b > \frac { 10 } { \sin 46 ^ { \circ } }$ D) $10 < b \leq \frac { 10 } { \sin 46 ^ { \circ } }$ E) $10 < b < \frac { 10 } { \sin 46 ^ { \circ } }$

Find Values for B Such That the Triangle Has Two 10≥b≥10sin⁡46∘10 \geq b \geq \frac { 10 } { \sin 46 ^ { \circ } }10≥b≥sin46∘10​

Find Values for B Such That the Triangle Has Two $10 \geq b \geq \frac { 10 } { \sin 46 ^ { \circ } }$