Find the projection of u onto v.Then write u as the sum of two orthogonal vectors, one of which is $\operatorname { proj } _ { \mathrm { v } } \mathbf { u }$ .
$\mathbf { u } = \langle 30,5 \rangle$ $\mathbf { v } = \langle 1 , - 6 \rangle$
A) $\langle 0,0 \rangle , \langle - 30,5 \rangle$
B) $\langle 0,0 \rangle , \langle 30,5 \rangle$
C) $\langle 0,0 \rangle , \langle - 1 , - 6 \rangle$
D) $\langle 0,0 \rangle , \langle 30 , - 5 \rangle$
E) $\langle 0,0 \rangle , \langle 1 , - 6 \rangle$

Question

Find the projection of u onto v.Then write u as the sum of two orthogonal vectors, one of which is $\operatorname { proj } _ { \mathrm { v } } \mathbf { u }$ . 
  $\mathbf { u } = \langle 30,5 \rangle$ $\mathbf { v } = \langle 1 , - 6 \rangle$  
A)  $\langle 0,0 \rangle , \langle - 30,5 \rangle$
B)  $\langle 0,0 \rangle , \langle 30,5 \rangle$
C)  $\langle 0,0 \rangle , \langle - 1 , - 6 \rangle$
D)  $\langle 0,0 \rangle , \langle 30 , - 5 \rangle$
E)  $\langle 0,0 \rangle , \langle 1 , - 6 \rangle$

Quizplus · Accepted Answer

The projection of u onto v is $\langle 0,0 \rangle$ because u and v are orthogonal. Therefore, u itself is the sum of $\langle 0,0 \rangle$ and $\langle 30,5 \rangle$.

Find the Projection of U onto V proj⁡vu\operatorname { proj } _ { \mathrm { v } } \mathbf { u }projv​u

Find the Projection of U onto V $\operatorname { proj } _ { \mathrm { v } } \mathbf { u }$