The forces acting on an object weighing W units on an inclined plane positioned at an angle of $\theta$ with the horizontal (see figure) are modeled by
$\mu W \sin \theta = W \tan \theta$
Where $\theta $ is the coefficient of friction.Solve the equation for $\theta $ and simplify the result.

A) $\mu = \tan \theta$
B) $\mu = \csc \theta$
C) $\mu = \sin \theta$
D) $\mu = \sec \theta$
E) $\mu = \cot \theta$

Question

The forces acting on an object weighing W units on an inclined plane positioned at an angle of $\theta$  with the horizontal (see figure) are modeled by 
 $\mu W \sin \theta = W \tan \theta$  
Where $\theta $ is the coefficient of friction.Solve the equation for $\theta $ and simplify the result.
  
A) $\mu = \tan \theta$ 
B) $\mu = \csc \theta$ 
C) $\mu = \sin \theta$ 
D) $\mu = \sec \theta$ 
E) $\mu = \cot \theta$

Quizplus · Accepted Answer

The Answer of The forces acting on an object weighing W units on an inclined plane positioned at an angle of $\theta$  with the horizontal (see figure) are modeled by 
 $\mu W \sin \theta = W \tan \theta$  
Where $\theta $ is the coefficient of friction.Solve the equation for $\theta $ and simplify the result.
  
A) $\mu = \tan \theta$ 
B) $\mu = \csc \theta$ 
C) $\mu = \sin \theta$ 
D) $\mu = \sec \theta$ 
E) $\mu = \cot \theta$

The Forces Acting on an Object Weighing W Units on an Inclined