Evaluate the expression.
$\frac { 1 } { \tan x + \cot x }$
A) $- \sin ^ { 2 } x$
B) $\sin x$
C) $\sin x \cos x$
D) $\cos ^ { 2 } x$
E)0

Question

Evaluate the expression. 
 $\frac { 1 } { \tan x + \cot x }$  
A) $- \sin ^ { 2 } x$
B) $\sin x$
C) $\sin x \cos x$
D) $\cos ^ { 2 } x$
E)0

Quizplus · Accepted Answer

The expression can be simplified by converting $\tan x$ and $\cot x$ to their sine and cosine equivalents, resulting in $\frac{1}{\frac{\sin x}{\cos x} + \frac{\cos x}{\sin x}}$. Simplifying further, we get $\frac{1}{\frac{\sin^2 x + \cos^2 x}{\sin x \cos x}}$, which simplifies to $\sin x \cos x$ because $\sin^2 x + \cos^2 x = 1$.

Evaluate the Expression 1tan⁡x+cot⁡x\frac { 1 } { \tan x + \cot x }tanx+cotx1​

Evaluate the Expression $\frac { 1 } { \tan x + \cot x }$