Solve the following equation.
$2 \sin x - 1 = 0$
A) $x = \frac { 2 \pi } { 3 } + 2 n \pi \text { and } x = \frac { 4 \pi } { 3 } + 2 n \pi$ , where n is an integer
B) $x = \frac { \pi } { 6 } + 2 n \pi \text { and } x = \frac { 5 \pi } { 6 } + 2 n \pi$ , where n is an integer
C) $x = \frac { \pi } { 3 } + 2 n \pi \text { and } x = \frac { 5 \pi } { 3 } + 2 n \pi$ , where n is an integer
D) $x = \frac { \pi } { 4 } + 2 n \pi \text { and } x = \frac { 5 \pi } { 4 } + 2 n \pi$ , where n is an integer
E) $x = \frac { 2 \pi } { 3 } + 2 n \pi \text { and } x = \frac { 4 \pi } { 3 } + 2 n \pi$ , where n is an integer.

Question

Solve the following equation. 
 $2 \sin x - 1 = 0$
A)  $x = \frac { 2 \pi } { 3 } + 2 n \pi \text { and } x = \frac { 4 \pi } { 3 } + 2 n \pi$ , where n is an integer
B)  $x = \frac { \pi } { 6 } + 2 n \pi \text { and } x = \frac { 5 \pi } { 6 } + 2 n \pi$ , where n is an integer
C)  $x = \frac { \pi } { 3 } + 2 n \pi \text { and } x = \frac { 5 \pi } { 3 } + 2 n \pi$ , where n is an integer
D)  $x = \frac { \pi } { 4 } + 2 n \pi \text { and } x = \frac { 5 \pi } { 4 } + 2 n \pi$ , where n is an integer
E)  $x = \frac { 2 \pi } { 3 } + 2 n \pi \text { and } x = \frac { 4 \pi } { 3 } + 2 n \pi$ , where n is an integer.

Quizplus · Accepted Answer

The Answer of Solve the following equation. 
 $2 \sin x - 1 = 0$
A)  $x = \frac { 2 \pi } { 3 } + 2 n \pi \text { and } x = \frac { 4 \pi } { 3 } + 2 n \pi$ , where n is an integer
B)  $x = \frac { \pi } { 6 } + 2 n \pi \text { and } x = \frac { 5 \pi } { 6 } + 2 n \pi$ , where n is an integer
C)  $x = \frac { \pi } { 3 } + 2 n \pi \text { and } x = \frac { 5 \pi } { 3 } + 2 n \pi$ , where n is an integer
D)  $x = \frac { \pi } { 4 } + 2 n \pi \text { and } x = \frac { 5 \pi } { 4 } + 2 n \pi$ , where n is an integer
E)  $x = \frac { 2 \pi } { 3 } + 2 n \pi \text { and } x = \frac { 4 \pi } { 3 } + 2 n \pi$ , where n is an integer.

Solve the Following Equation 2sin⁡x−1=02 \sin x - 1 = 02sinx−1=0

Solve the Following Equation $2 \sin x - 1 = 0$